Electronvolts to Foot-pounds Converter
Convert electronvolts (eV) to foot-pounds (ft·lbf)
Result
1 eV = 1.1817048 × 10⁻¹⁹ ft·lbf
1 eV in other units
- 1Enter a valueType the number to convert
- 2Pick the unitsChoose what to convert from and to
- 3Read the resultSee it in every other unit too
How to convert electronvolts to foot-pounds
There are 8.46235 × 10¹⁸ electronvolts in one foot-pound, so divide the number of electronvolts by 8.46235 × 10¹⁸.
ft·lbf = eV ÷ 8.46235 × 10¹⁸
1 eV = 1.181705 × 10⁻¹⁹ ft·lbf · 1 ft·lbf = 8.46235 × 10¹⁸ eV
Worked example
To convert 5 electronvolts to foot-pounds: 5 eV ÷ 8.46235 × 10¹⁸ = 5.908524 × 10⁻¹⁹ ft·lbf.
About electronvolts (eV)
An electronvolt is the energy an electron gains across one volt, used in atomic and particle physics.
About foot-pounds (ft·lbf)
A foot-pound is the work of one pound-force over one foot, used in US engineering.
More conversions
Electronvolts to other units
Frequently asked questions
How many foot-pounds are in one electronvolt?
One electronvolt equals 1.181705 × 10⁻¹⁹ foot-pounds.
How many electronvolts are in one foot-pound?
One foot-pound equals 8.46235 × 10¹⁸ electronvolts.
How do I convert electronvolts to foot-pounds?
Use the formula ft·lbf = eV ÷ 8.46235 × 10¹⁸. For example, 5 eV ÷ 8.46235 × 10¹⁸ = 5.908524 × 10⁻¹⁹ ft·lbf.