Foot-pounds to Electronvolts Converter
Convert foot-pounds (ft·lbf) to electronvolts (eV)
Result
1 ft·lbf = 8.46235 × 10¹⁸ eV
1 ft·lbf in other units
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How to convert foot-pounds to electronvolts
One foot-pound equals 8.46235 × 10¹⁸ electronvolts, so multiply the number of foot-pounds by 8.46235 × 10¹⁸.
eV = ft·lbf × 8.46235 × 10¹⁸
1 ft·lbf = 8.46235 × 10¹⁸ eV · 1 eV = 1.181705 × 10⁻¹⁹ ft·lbf
Worked example
To convert 5 foot-pounds to electronvolts: 5 ft·lbf × 8.46235 × 10¹⁸ = 4.231175 × 10¹⁹ eV.
About foot-pounds (ft·lbf)
A foot-pound is the work of one pound-force over one foot, used in US engineering.
About electronvolts (eV)
An electronvolt is the energy an electron gains across one volt, used in atomic and particle physics.
More conversions
Foot-pounds to other units
Frequently asked questions
How many electronvolts are in one foot-pound?
One foot-pound equals 8.46235 × 10¹⁸ electronvolts.
How many foot-pounds are in one electronvolt?
One electronvolt equals 1.181705 × 10⁻¹⁹ foot-pounds.
How do I convert foot-pounds to electronvolts?
Use the formula eV = ft·lbf × 8.46235 × 10¹⁸. For example, 5 ft·lbf × 8.46235 × 10¹⁸ = 4.231175 × 10¹⁹ eV.